SOLUCIONARIO ESTÁTICA
1 -0.55385 TAD - 1.02857 TAE +4.32-071 -0.73846 TAD +0.68571TA==
Cx-0.8 (2.6kN) + 0.8 (2.8 kN) = 0 → G-0
ΣFY=0: Cy+0.6 (2.6 KN) + 2.2 (2.8KN)-(3.6 KN)=0
Cy = 1.800 kN
Et₂ = OG-24 (2.6kN) - 24 (28 kN) = 0
Cz=4.801N
C= (1.800 KN); + (4.80 KN) R